Model 3 Opening both taps and leaks Practice Questions Answers Test with Solutions & More Shortcuts
pipes & cisterns PRACTICE TEST [3 - EXERCISES]
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
Question : 21 [SSC CGL Prelim 2008]
A tank has a leak which would empty the completely filled tank in 10 hours. If the tank is full of water and a tap is opened which admits 4 litres of water per minute in the tank, the leak takes 15 hours to empty the tank. How many litres of water does the tank hold ?
a) 7200 L
b) 1200 L
c) 2400 L
d) 4500 L
Answer »Answer: (a)
Let the capacity of the tank = x litres
According to the question,
Quantity of water emptied by the leak in 1 hour = $x/10$ litres
Qunatity of water filled by the tap in 1 hour = 240 litres
According to the question,
$x/10 - x/15$ = 240
${3x - 2x}/30 = 240$
$x/30$ = 240
$x$ = 240 × 30 = 7200 litres
Question : 22 [SSC GL Tier-I 2013]
Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes, P is turned off. In how many more minutes will Q fill the cistern ?
a) 8$1/4$ minutes
b) 8 minutes
c) 7 minutes
d) 7$1/2$ minutes
Answer »Answer: (a)
Using Rule 1,Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?Required time = $({xy}/{x + y})$ hrs
Part of the tank filled in 3 minutes by pipes P and Q
= $3(1/12 + 1/15)$
= $3({5 + 4}/60) = {3 × 9}/60 = 9/20$
So, Remaining part
= 1– $9/20 = 11/20$
Time taken by Q
= $11/20 × 15 = 33/4 = 8{1}/4$ minutes
Question : 23 [SSC SO 2007]
A tank can be filled with water by two pipes A and B together in 36 minutes. If the pipe B was stopped after 30 minutes, the tank is filled in 40 minutes. The pipe B can alone fill the tank in
a) 90 minutes
b) 75 minutes
c) 45 minutes
d) 60 minutes
Answer »Answer: (a)
Let the pipe B fill the tank in x minutes.
Part of the tank filled by pipes A and B in 1 minute = $1/36$
Part of the tank filled by pipe A in 1 minute
= $1/36 - 1/x$
According to the question,
30 × $1/x + 40(1/36 - 1/x) = 1$
$30/x + 10/9 - 40/x$ = 1
$40/x - 30/x = 10/9 - 1$
$10/x = 1/9 ⇒ x = 90$ minutes
Question : 24 [SSC Delhi Police S.I.2012]
Two pipes A and B can fill a tank in 6 hours and 8 hours respectively. If both the pipes are opened together, then after how many hours should B be closed so that the tank is full in 4 hours?
a) $8/3$ hrs
b) 2 hrs
c) $2/3$ hrs
d) 1hrs
Answer »Answer: (a)
Part of the tank filled in 4 hours by pipe A = $4/6 = 2/3$
Remaining part = ${1 - 2}/3 = 1/3$
Time taken by pipe B in filling $1/3$ part = $8/3$ hours
Using Rule 8,
Here, x = 6, y = 8, t = 4
Required time = $[y(1 –{t/x})]$ hours
= $[8(1 - 4/6)]$ hours = $8/3$ hours
Question : 25 [SSC CGL Tier-II 2016]
A water tap fills a tub in ‘p’ hours and a sink at the bottom empties it in ‘q’ hours. If p < q and both tap and sink are open, the tank is filled in ‘r’ hours; then
a) r = p - q
b) r = p + q
c) $1/r = 1/p + 1/q$
d) $1/r = 1/p - 1/q$
Answer »Answer: (d)
Since, P < q,
On opening pipe and sink together,
Part of the tub filled in 1 hour
= $1/P - 1/q$
Clearly, $1/P - 1/q = 1/r$
IMPORTANT quantitative aptitude EXERCISES
Model 3 Opening both taps and leaks Shortcuts »
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